Split an array with commas, except the last item with “and” e.g. (['one', 'two', 'three', 'four'] ->...












6














I want to convert the array ['one', 'two', 'three', 'four'] into one, two, three and four



Note that the first items have a comma, and but there is the word and between the second-last one and the last one.



The best solution I've come up with:



a.reduce( (res, v, i) => i === a.length - 2 ? res + v + ' and ' : res + v + ( i == a.length -1? '' : ', '), '' )


It's based on adding the commas at the end -- with the exception of the second-last one (a.length - 2) and with a way to avoid the last comma (a.length - 2).



SURELY there must be a better, neater, more intelligent way to do this?



It's a difficult topic to search on search engines because it contains the word "and"...






javascript arrays string







share|improve this question






















  • SURELY you value the serial/Oxford comma?!?
    – Argalatyr
    12 mins ago










  • You mean I should return one, two, three, and four?
    – Merc
    15 secs ago
















6














I want to convert the array ['one', 'two', 'three', 'four'] into one, two, three and four



Note that the first items have a comma, and but there is the word and between the second-last one and the last one.



The best solution I've come up with:



a.reduce( (res, v, i) => i === a.length - 2 ? res + v + ' and ' : res + v + ( i == a.length -1? '' : ', '), '' )


It's based on adding the commas at the end -- with the exception of the second-last one (a.length - 2) and with a way to avoid the last comma (a.length - 2).



SURELY there must be a better, neater, more intelligent way to do this?



It's a difficult topic to search on search engines because it contains the word "and"...






javascript arrays string







share|improve this question






















  • SURELY you value the serial/Oxford comma?!?
    – Argalatyr
    12 mins ago










  • You mean I should return one, two, three, and four?
    – Merc
    15 secs ago














6












6








6







I want to convert the array ['one', 'two', 'three', 'four'] into one, two, three and four



Note that the first items have a comma, and but there is the word and between the second-last one and the last one.



The best solution I've come up with:



a.reduce( (res, v, i) => i === a.length - 2 ? res + v + ' and ' : res + v + ( i == a.length -1? '' : ', '), '' )


It's based on adding the commas at the end -- with the exception of the second-last one (a.length - 2) and with a way to avoid the last comma (a.length - 2).



SURELY there must be a better, neater, more intelligent way to do this?



It's a difficult topic to search on search engines because it contains the word "and"...






javascript arrays string







share|improve this question













I want to convert the array ['one', 'two', 'three', 'four'] into one, two, three and four



Note that the first items have a comma, and but there is the word and between the second-last one and the last one.



The best solution I've come up with:



a.reduce( (res, v, i) => i === a.length - 2 ? res + v + ' and ' : res + v + ( i == a.length -1? '' : ', '), '' )


It's based on adding the commas at the end -- with the exception of the second-last one (a.length - 2) and with a way to avoid the last comma (a.length - 2).



SURELY there must be a better, neater, more intelligent way to do this?



It's a difficult topic to search on search engines because it contains the word "and"...






javascript arrays string




javascript arrays string






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 1 hour ago









Merc

6,76294785




6,76294785












  • SURELY you value the serial/Oxford comma?!?
    – Argalatyr
    12 mins ago










  • You mean I should return one, two, three, and four?
    – Merc
    15 secs ago


















  • SURELY you value the serial/Oxford comma?!?
    – Argalatyr
    12 mins ago










  • You mean I should return one, two, three, and four?
    – Merc
    15 secs ago
















SURELY you value the serial/Oxford comma?!?
– Argalatyr
12 mins ago




SURELY you value the serial/Oxford comma?!?
– Argalatyr
12 mins ago












You mean I should return one, two, three, and four?
– Merc
15 secs ago




You mean I should return one, two, three, and four?
– Merc
15 secs ago












4 Answers
4






active

oldest

votes


















8














One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:






const input = ['one', 'two', 'three', 'four'];

const last = input.pop();

const result = input.join(', ') + ' and ' + last;

console.log(result);








share|improve this answer





















  • Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
    – user2864740
    1 hour ago






  • 1




    I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
    – Merc
    1 hour ago










  • I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
    – Merc
    1 hour ago






  • 2




    Very nice, thought the lack of the Oxford comma is killing me.
    – Mark Meyer
    1 hour ago










  • As an echo to an other answer, you may want to push last back in input (you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
    – Kaiido
    55 mins ago



















2














Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.






let input = ['one', 'two', 'three', 'four'];

let removed = input.splice(-2, 2);

input.push(removed.join(" and "));    



console.log(input.join(", "));








share|improve this answer































    1














    You can use Array.prototype.slice()



    Code:






    const input = ['one', 'two', 'three', 'four'];
    
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
    
  
    
console.log(result);





    And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']



    Code:






    const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
    
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
    

    
console.log(result);








    share|improve this answer























    • Easy to introduce subtle issues that'll be found later (outside of a restricted set of input): ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
      – user2864740
      1 hour ago












    • @user2864740 Good comment, thanks
      – Yosvel Quintero
      1 hour ago






    • 1




      @user2864740 I have updated my answer for that type of input data..
      – Yosvel Quintero
      1 hour ago



















    1














    I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:






    function makeCommaSeparatedString(arr, useOxfordComma) {
    
    const listStart = arr.slice(0, -1).join(', ');
    
    const listEnd = arr.slice(-1);
    
    const conjunction = arr.length <= 1 ? '' :
    
        useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
    

    
    return [listStart, listEnd].join(conjunction);
    
}
    

    
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
    
// one, two, three and four
    
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
    
// one, two, three, and four
    
console.log(makeCommaSeparatedString(['one', 'two'], true));
    
// one and two
    
console.log(makeCommaSeparatedString(['one']));
    
// one
    
console.log(makeCommaSeparatedString());
    
//








    share|improve this answer








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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      8














      One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:






      const input = ['one', 'two', 'three', 'four'];
      
const last = input.pop();
      
const result = input.join(', ') + ' and ' + last;
      
console.log(result);








      share|improve this answer





















      • Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
        – user2864740
        1 hour ago






      • 1




        I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
        – Merc
        1 hour ago










      • I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
        – Merc
        1 hour ago






      • 2




        Very nice, thought the lack of the Oxford comma is killing me.
        – Mark Meyer
        1 hour ago










      • As an echo to an other answer, you may want to push last back in input (you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
        – Kaiido
        55 mins ago
















      8














      One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:






      const input = ['one', 'two', 'three', 'four'];
      
const last = input.pop();
      
const result = input.join(', ') + ' and ' + last;
      
console.log(result);








      share|improve this answer





















      • Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
        – user2864740
        1 hour ago






      • 1




        I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
        – Merc
        1 hour ago










      • I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
        – Merc
        1 hour ago






      • 2




        Very nice, thought the lack of the Oxford comma is killing me.
        – Mark Meyer
        1 hour ago










      • As an echo to an other answer, you may want to push last back in input (you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
        – Kaiido
        55 mins ago














      8












      8








      8






      One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:






      const input = ['one', 'two', 'three', 'four'];
      
const last = input.pop();
      
const result = input.join(', ') + ' and ' + last;
      
console.log(result);








      share|improve this answer












      One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:






      const input = ['one', 'two', 'three', 'four'];
      
const last = input.pop();
      
const result = input.join(', ') + ' and ' + last;
      
console.log(result);








      const input = ['one', 'two', 'three', 'four'];
      
const last = input.pop();
      
const result = input.join(', ') + ' and ' + last;
      
console.log(result);





      const input = ['one', 'two', 'three', 'four'];
      
const last = input.pop();
      
const result = input.join(', ') + ' and ' + last;
      
console.log(result);






      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered 1 hour ago









      CertainPerformance

      73.4k143454




      73.4k143454












      • Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
        – user2864740
        1 hour ago






      • 1




        I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
        – Merc
        1 hour ago










      • I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
        – Merc
        1 hour ago






      • 2




        Very nice, thought the lack of the Oxford comma is killing me.
        – Mark Meyer
        1 hour ago










      • As an echo to an other answer, you may want to push last back in input (you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
        – Kaiido
        55 mins ago


















      • Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
        – user2864740
        1 hour ago






      • 1




        I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
        – Merc
        1 hour ago










      • I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
        – Merc
        1 hour ago






      • 2




        Very nice, thought the lack of the Oxford comma is killing me.
        – Mark Meyer
        1 hour ago










      • As an echo to an other answer, you may want to push last back in input (you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
        – Kaiido
        55 mins ago
















      Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
      – user2864740
      1 hour ago




      Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
      – user2864740
      1 hour ago




      1




      1




      I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
      – Merc
      1 hour ago




      I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
      – Merc
      1 hour ago












      I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
      – Merc
      1 hour ago




      I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
      – Merc
      1 hour ago




      2




      2




      Very nice, thought the lack of the Oxford comma is killing me.
      – Mark Meyer
      1 hour ago




      Very nice, thought the lack of the Oxford comma is killing me.
      – Mark Meyer
      1 hour ago












      As an echo to an other answer, you may want to push last back in input (you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
      – Kaiido
      55 mins ago




      As an echo to an other answer, you may want to push last back in input (you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
      – Kaiido
      55 mins ago













      2














      Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.






      let input = ['one', 'two', 'three', 'four'];
      
let removed = input.splice(-2, 2);
      
input.push(removed.join(" and "));    
      

      
console.log(input.join(", "));








      share|improve this answer




























        2














        Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.






        let input = ['one', 'two', 'three', 'four'];
        
let removed = input.splice(-2, 2);
        
input.push(removed.join(" and "));    
        

        
console.log(input.join(", "));








        share|improve this answer


























          2












          2








          2






          Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.






          let input = ['one', 'two', 'three', 'four'];
          
let removed = input.splice(-2, 2);
          
input.push(removed.join(" and "));    
          

          
console.log(input.join(", "));








          share|improve this answer














          Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.






          let input = ['one', 'two', 'three', 'four'];
          
let removed = input.splice(-2, 2);
          
input.push(removed.join(" and "));    
          

          
console.log(input.join(", "));








          let input = ['one', 'two', 'three', 'four'];
          
let removed = input.splice(-2, 2);
          
input.push(removed.join(" and "));    
          

          
console.log(input.join(", "));





          let input = ['one', 'two', 'three', 'four'];
          
let removed = input.splice(-2, 2);
          
input.push(removed.join(" and "));    
          

          
console.log(input.join(", "));






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 21 mins ago

























          answered 59 mins ago









          Shidersz

          3,3011425




          3,3011425























              1














              You can use Array.prototype.slice()



              Code:






              const input = ['one', 'two', 'three', 'four'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              
  
              
console.log(result);





              And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']



              Code:






              const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              

              
console.log(result);








              share|improve this answer























              • Easy to introduce subtle issues that'll be found later (outside of a restricted set of input): ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
                – user2864740
                1 hour ago












              • @user2864740 Good comment, thanks
                – Yosvel Quintero
                1 hour ago






              • 1




                @user2864740 I have updated my answer for that type of input data..
                – Yosvel Quintero
                1 hour ago
















              1














              You can use Array.prototype.slice()



              Code:






              const input = ['one', 'two', 'three', 'four'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              
  
              
console.log(result);





              And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']



              Code:






              const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              

              
console.log(result);








              share|improve this answer























              • Easy to introduce subtle issues that'll be found later (outside of a restricted set of input): ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
                – user2864740
                1 hour ago












              • @user2864740 Good comment, thanks
                – Yosvel Quintero
                1 hour ago






              • 1




                @user2864740 I have updated my answer for that type of input data..
                – Yosvel Quintero
                1 hour ago














              1












              1








              1






              You can use Array.prototype.slice()



              Code:






              const input = ['one', 'two', 'three', 'four'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              
  
              
console.log(result);





              And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']



              Code:






              const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              

              
console.log(result);








              share|improve this answer














              You can use Array.prototype.slice()



              Code:






              const input = ['one', 'two', 'three', 'four'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              
  
              
console.log(result);





              And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']



              Code:






              const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              

              
console.log(result);








              const input = ['one', 'two', 'three', 'four'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              
  
              
console.log(result);





              const input = ['one', 'two', 'three', 'four'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              
  
              
console.log(result);





              const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              

              
console.log(result);





              const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
              
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
              

              
console.log(result);






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 57 mins ago

























              answered 1 hour ago









              Yosvel Quintero

              10.9k42229




              10.9k42229












              • Easy to introduce subtle issues that'll be found later (outside of a restricted set of input): ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
                – user2864740
                1 hour ago












              • @user2864740 Good comment, thanks
                – Yosvel Quintero
                1 hour ago






              • 1




                @user2864740 I have updated my answer for that type of input data..
                – Yosvel Quintero
                1 hour ago


















              • Easy to introduce subtle issues that'll be found later (outside of a restricted set of input): ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
                – user2864740
                1 hour ago












              • @user2864740 Good comment, thanks
                – Yosvel Quintero
                1 hour ago






              • 1




                @user2864740 I have updated my answer for that type of input data..
                – Yosvel Quintero
                1 hour ago
















              Easy to introduce subtle issues that'll be found later (outside of a restricted set of input): ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
              – user2864740
              1 hour ago






              Easy to introduce subtle issues that'll be found later (outside of a restricted set of input): ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
              – user2864740
              1 hour ago














              @user2864740 Good comment, thanks
              – Yosvel Quintero
              1 hour ago




              @user2864740 Good comment, thanks
              – Yosvel Quintero
              1 hour ago




              1




              1




              @user2864740 I have updated my answer for that type of input data..
              – Yosvel Quintero
              1 hour ago




              @user2864740 I have updated my answer for that type of input data..
              – Yosvel Quintero
              1 hour ago











              1














              I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:






              function makeCommaSeparatedString(arr, useOxfordComma) {
              
    const listStart = arr.slice(0, -1).join(', ');
              
    const listEnd = arr.slice(-1);
              
    const conjunction = arr.length <= 1 ? '' :
              
        useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
              

              
    return [listStart, listEnd].join(conjunction);
              
}
              

              
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
              
// one, two, three and four
              
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
              
// one, two, three, and four
              
console.log(makeCommaSeparatedString(['one', 'two'], true));
              
// one and two
              
console.log(makeCommaSeparatedString(['one']));
              
// one
              
console.log(makeCommaSeparatedString());
              
//








              share|improve this answer








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                1














                I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:






                function makeCommaSeparatedString(arr, useOxfordComma) {
                
    const listStart = arr.slice(0, -1).join(', ');
                
    const listEnd = arr.slice(-1);
                
    const conjunction = arr.length <= 1 ? '' :
                
        useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
                

                
    return [listStart, listEnd].join(conjunction);
                
}
                

                
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
                
// one, two, three and four
                
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
                
// one, two, three, and four
                
console.log(makeCommaSeparatedString(['one', 'two'], true));
                
// one and two
                
console.log(makeCommaSeparatedString(['one']));
                
// one
                
console.log(makeCommaSeparatedString());
                
//








                share|improve this answer








                New contributor




                Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





















                  1












                  1








                  1






                  I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:






                  function makeCommaSeparatedString(arr, useOxfordComma) {
                  
    const listStart = arr.slice(0, -1).join(', ');
                  
    const listEnd = arr.slice(-1);
                  
    const conjunction = arr.length <= 1 ? '' :
                  
        useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
                  

                  
    return [listStart, listEnd].join(conjunction);
                  
}
                  

                  
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
                  
// one, two, three and four
                  
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
                  
// one, two, three, and four
                  
console.log(makeCommaSeparatedString(['one', 'two'], true));
                  
// one and two
                  
console.log(makeCommaSeparatedString(['one']));
                  
// one
                  
console.log(makeCommaSeparatedString());
                  
//








                  share|improve this answer








                  New contributor




                  Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:






                  function makeCommaSeparatedString(arr, useOxfordComma) {
                  
    const listStart = arr.slice(0, -1).join(', ');
                  
    const listEnd = arr.slice(-1);
                  
    const conjunction = arr.length <= 1 ? '' :
                  
        useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
                  

                  
    return [listStart, listEnd].join(conjunction);
                  
}
                  

                  
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
                  
// one, two, three and four
                  
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
                  
// one, two, three, and four
                  
console.log(makeCommaSeparatedString(['one', 'two'], true));
                  
// one and two
                  
console.log(makeCommaSeparatedString(['one']));
                  
// one
                  
console.log(makeCommaSeparatedString());
                  
// 








                  function makeCommaSeparatedString(arr, useOxfordComma) {
                  
    const listStart = arr.slice(0, -1).join(', ');
                  
    const listEnd = arr.slice(-1);
                  
    const conjunction = arr.length <= 1 ? '' :
                  
        useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
                  

                  
    return [listStart, listEnd].join(conjunction);
                  
}
                  

                  
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
                  
// one, two, three and four
                  
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
                  
// one, two, three, and four
                  
console.log(makeCommaSeparatedString(['one', 'two'], true));
                  
// one and two
                  
console.log(makeCommaSeparatedString(['one']));
                  
// one
                  
console.log(makeCommaSeparatedString());
                  
// 





                  function makeCommaSeparatedString(arr, useOxfordComma) {
                  
    const listStart = arr.slice(0, -1).join(', ');
                  
    const listEnd = arr.slice(-1);
                  
    const conjunction = arr.length <= 1 ? '' :
                  
        useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
                  

                  
    return [listStart, listEnd].join(conjunction);
                  
}
                  

                  
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
                  
// one, two, three and four
                  
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
                  
// one, two, three, and four
                  
console.log(makeCommaSeparatedString(['one', 'two'], true));
                  
// one and two
                  
console.log(makeCommaSeparatedString(['one']));
                  
// one
                  
console.log(makeCommaSeparatedString());
                  
//






                  share|improve this answer








                  New contributor




                  Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  share|improve this answer



                  share|improve this answer






                  New contributor




                  Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  answered 29 mins ago









                  Jug

                  261




                  261




                  New contributor




                  Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.





                  New contributor





                  Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






























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