Print specific keys and values from a deep nested dictionary in python 3.X
6
I am new to python and I've tried to search but can seem to find a sample of what I am trying to accomplish. Any ideas are much appreciated. I am working with a nested dictionary with lots of key and values but I only want to print specific ones using a filtered list variable.
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": true, "is_up": true, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
I would like to a filter through it and choose which keys and values to print out
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
and achieve a out out of
peers: 15.1.1.1
remote_id: 15.1.1.1
remote_as: 65002
uptime: 13002
python python-3.x
asked 4 hours ago
JHCTac
585
add a comment |
6
I am new to python and I've tried to search but can seem to find a sample of what I am trying to accomplish. Any ideas are much appreciated. I am working with a nested dictionary with lots of key and values but I only want to print specific ones using a filtered list variable.
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": true, "is_up": true, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
I would like to a filter through it and choose which keys and values to print out
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
and achieve a out out of
peers: 15.1.1.1
remote_id: 15.1.1.1
remote_as: 65002
uptime: 13002
python python-3.x
asked 4 hours ago
JHCTac
585
add a comment |
6
6
6
0
I am new to python and I've tried to search but can seem to find a sample of what I am trying to accomplish. Any ideas are much appreciated. I am working with a nested dictionary with lots of key and values but I only want to print specific ones using a filtered list variable.
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": true, "is_up": true, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
I would like to a filter through it and choose which keys and values to print out
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
and achieve a out out of
peers: 15.1.1.1
remote_id: 15.1.1.1
remote_as: 65002
uptime: 13002
python python-3.x
asked 4 hours ago
JHCTac
585
I am new to python and I've tried to search but can seem to find a sample of what I am trying to accomplish. Any ideas are much appreciated. I am working with a nested dictionary with lots of key and values but I only want to print specific ones using a filtered list variable.
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": true, "is_up": true, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
I would like to a filter through it and choose which keys and values to print out
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
and achieve a out out of
peers: 15.1.1.1
remote_id: 15.1.1.1
remote_as: 65002
uptime: 13002
python python-3.x
python python-3.x
asked 4 hours ago
JHCTac
585
asked 4 hours ago
JHCTac
585
asked 4 hours ago
JHCTac
585
asked 4 hours ago
JHCTac
585
asked 4 hours ago
JHCTac
585
585
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
8
Use recursion and isinstance:
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": True, "is_up": True, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
def seek_keys(d, key_list):
for k, v in d.items():
if k in key_list:
if isinstance(v, dict):
print(k + ": " + list(v.keys())[0])
else:
print(k + ": " + str(v))
if isinstance(v, dict):
seek_keys(v, key_list)
seek_keys(my_nested_dict, filtered_list)
Note: There is a built in assumption here that if you ever want the "value" from a key whose value is another dictionary, you get the first key.
edited 4 hours ago
U9-Forward
12.8k21136
answered 4 hours ago
JacobIRR
3,22521027
Hi Jacob I tried that code however I am getting the following error: TypeError: 'dict_keys' object does not support indexing
– JHCTac
4 hours ago
1
Nice answer man.
– U9-Forward
4 hours ago
1
@JHCTac Now i edited for Jacob
– U9-Forward
4 hours ago
Wow that worked perfectly @U9-Forward and @JacobIRR! That is exactly what I was looking for.
– JHCTac
4 hours ago
1
@JHCTac Nice to help,
– U9-Forward
4 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
8
Use recursion and isinstance:
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": True, "is_up": True, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
def seek_keys(d, key_list):
for k, v in d.items():
if k in key_list:
if isinstance(v, dict):
print(k + ": " + list(v.keys())[0])
else:
print(k + ": " + str(v))
if isinstance(v, dict):
seek_keys(v, key_list)
seek_keys(my_nested_dict, filtered_list)
Note: There is a built in assumption here that if you ever want the "value" from a key whose value is another dictionary, you get the first key.
edited 4 hours ago
U9-Forward
12.8k21136
answered 4 hours ago
JacobIRR
3,22521027
Hi Jacob I tried that code however I am getting the following error: TypeError: 'dict_keys' object does not support indexing
– JHCTac
4 hours ago
1
Nice answer man.
– U9-Forward
4 hours ago
1
@JHCTac Now i edited for Jacob
– U9-Forward
4 hours ago
Wow that worked perfectly @U9-Forward and @JacobIRR! That is exactly what I was looking for.
– JHCTac
4 hours ago
1
@JHCTac Nice to help,
– U9-Forward
4 hours ago
add a comment |
8
Use recursion and isinstance:
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": True, "is_up": True, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
def seek_keys(d, key_list):
for k, v in d.items():
if k in key_list:
if isinstance(v, dict):
print(k + ": " + list(v.keys())[0])
else:
print(k + ": " + str(v))
if isinstance(v, dict):
seek_keys(v, key_list)
seek_keys(my_nested_dict, filtered_list)
Note: There is a built in assumption here that if you ever want the "value" from a key whose value is another dictionary, you get the first key.
edited 4 hours ago
U9-Forward
12.8k21136
answered 4 hours ago
JacobIRR
3,22521027
Hi Jacob I tried that code however I am getting the following error: TypeError: 'dict_keys' object does not support indexing
– JHCTac
4 hours ago
1
Nice answer man.
– U9-Forward
4 hours ago
1
@JHCTac Now i edited for Jacob
– U9-Forward
4 hours ago
Wow that worked perfectly @U9-Forward and @JacobIRR! That is exactly what I was looking for.
– JHCTac
4 hours ago
1
@JHCTac Nice to help,
– U9-Forward
4 hours ago
add a comment |
8
8
8
Use recursion and isinstance:
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": True, "is_up": True, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
def seek_keys(d, key_list):
for k, v in d.items():
if k in key_list:
if isinstance(v, dict):
print(k + ": " + list(v.keys())[0])
else:
print(k + ": " + str(v))
if isinstance(v, dict):
seek_keys(v, key_list)
seek_keys(my_nested_dict, filtered_list)
Note: There is a built in assumption here that if you ever want the "value" from a key whose value is another dictionary, you get the first key.
edited 4 hours ago
U9-Forward
12.8k21136
answered 4 hours ago
JacobIRR
3,22521027
Use recursion and isinstance:
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": True, "is_up": True, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
def seek_keys(d, key_list):
for k, v in d.items():
if k in key_list:
if isinstance(v, dict):
print(k + ": " + list(v.keys())[0])
else:
print(k + ": " + str(v))
if isinstance(v, dict):
seek_keys(v, key_list)
seek_keys(my_nested_dict, filtered_list)
Note: There is a built in assumption here that if you ever want the "value" from a key whose value is another dictionary, you get the first key.
edited 4 hours ago
U9-Forward
12.8k21136
answered 4 hours ago
JacobIRR
3,22521027
edited 4 hours ago
U9-Forward
12.8k21136
edited 4 hours ago
U9-Forward
12.8k21136
edited 4 hours ago
U9-Forward
12.8k21136
12.8k21136
answered 4 hours ago
JacobIRR
3,22521027
answered 4 hours ago
JacobIRR
3,22521027
answered 4 hours ago
JacobIRR
3,22521027
3,22521027
Hi Jacob I tried that code however I am getting the following error: TypeError: 'dict_keys' object does not support indexing
– JHCTac
4 hours ago
1
Nice answer man.
– U9-Forward
4 hours ago
1
@JHCTac Now i edited for Jacob
– U9-Forward
4 hours ago
Wow that worked perfectly @U9-Forward and @JacobIRR! That is exactly what I was looking for.
– JHCTac
4 hours ago
1
@JHCTac Nice to help,
– U9-Forward
4 hours ago
add a comment |
Hi Jacob I tried that code however I am getting the following error: TypeError: 'dict_keys' object does not support indexing
– JHCTac
4 hours ago
1
Nice answer man.
– U9-Forward
4 hours ago
1
@JHCTac Now i edited for Jacob
– U9-Forward
4 hours ago
Wow that worked perfectly @U9-Forward and @JacobIRR! That is exactly what I was looking for.
– JHCTac
4 hours ago
1
@JHCTac Nice to help,
– U9-Forward
4 hours ago
Hi Jacob I tried that code however I am getting the following error: TypeError: 'dict_keys' object does not support indexing
– JHCTac
4 hours ago
Hi Jacob I tried that code however I am getting the following error: TypeError: 'dict_keys' object does not support indexing
– JHCTac
4 hours ago
1
1
Nice answer man.
– U9-Forward
4 hours ago
Nice answer man.
– U9-Forward
4 hours ago
1
1
@JHCTac Now i edited for Jacob
– U9-Forward
4 hours ago
@JHCTac Now i edited for Jacob
– U9-Forward
4 hours ago
Wow that worked perfectly @U9-Forward and @JacobIRR! That is exactly what I was looking for.
– JHCTac
4 hours ago
Wow that worked perfectly @U9-Forward and @JacobIRR! That is exactly what I was looking for.
– JHCTac
4 hours ago
1
1
@JHCTac Nice to help,
– U9-Forward
4 hours ago
@JHCTac Nice to help,
– U9-Forward
4 hours ago
add a comment |
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