How does Slither.io resolve head-on collisions?
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In Slither.io, whenever I run into another snake head on, I seem to lose the exchange and die while my opponent lives on. It's most apparent when there is a fresh kill and we're both racing (boosting) from opposite ends of the former snake until we inevitably meet in the middle.
I'm sure this is just a bit of confirmation bias, but when two snakes run into each other head on, how does the game determine which one survives and which one becomes snake food?
For anyone not familiar with this online game: slither.io is a large-field, multi-player game where you move your "snake" around trying to avoid running into others while causing others to run into you.
slither.io
asked Jun 3 '16 at 17:48
Robert Cartaino♦
161211
add a comment |
up vote
12
down vote
favorite
In Slither.io, whenever I run into another snake head on, I seem to lose the exchange and die while my opponent lives on. It's most apparent when there is a fresh kill and we're both racing (boosting) from opposite ends of the former snake until we inevitably meet in the middle.
I'm sure this is just a bit of confirmation bias, but when two snakes run into each other head on, how does the game determine which one survives and which one becomes snake food?
For anyone not familiar with this online game: slither.io is a large-field, multi-player game where you move your "snake" around trying to avoid running into others while causing others to run into you.
slither.io
asked Jun 3 '16 at 17:48
Robert Cartaino♦
161211
1
If I had to guess it is based on which snake moves first. Which snake moves first? Well... maybe it is the one that was created first. Or they get a random id, and they are enumerated by id. I am mostly just guessing here.
– Sumurai8
Jun 3 '16 at 19:32
add a comment |
up vote
12
down vote
favorite
up vote
12
down vote
favorite
In Slither.io, whenever I run into another snake head on, I seem to lose the exchange and die while my opponent lives on. It's most apparent when there is a fresh kill and we're both racing (boosting) from opposite ends of the former snake until we inevitably meet in the middle.
I'm sure this is just a bit of confirmation bias, but when two snakes run into each other head on, how does the game determine which one survives and which one becomes snake food?
For anyone not familiar with this online game: slither.io is a large-field, multi-player game where you move your "snake" around trying to avoid running into others while causing others to run into you.
slither.io
asked Jun 3 '16 at 17:48
Robert Cartaino♦
161211
In Slither.io, whenever I run into another snake head on, I seem to lose the exchange and die while my opponent lives on. It's most apparent when there is a fresh kill and we're both racing (boosting) from opposite ends of the former snake until we inevitably meet in the middle.
I'm sure this is just a bit of confirmation bias, but when two snakes run into each other head on, how does the game determine which one survives and which one becomes snake food?
For anyone not familiar with this online game: slither.io is a large-field, multi-player game where you move your "snake" around trying to avoid running into others while causing others to run into you.
slither.io
slither.io
asked Jun 3 '16 at 17:48
Robert Cartaino♦
161211
asked Jun 3 '16 at 17:48
Robert Cartaino♦
161211
edited Jun 3 '16 at 19:39
asked Jun 3 '16 at 17:48
Robert Cartaino♦
161211
asked Jun 3 '16 at 17:48
Robert Cartaino♦
161211
asked Jun 3 '16 at 17:48
Robert Cartaino♦
161211
161211
1
If I had to guess it is based on which snake moves first. Which snake moves first? Well... maybe it is the one that was created first. Or they get a random id, and they are enumerated by id. I am mostly just guessing here.
– Sumurai8
Jun 3 '16 at 19:32
add a comment |
1
If I had to guess it is based on which snake moves first. Which snake moves first? Well... maybe it is the one that was created first. Or they get a random id, and they are enumerated by id. I am mostly just guessing here.
– Sumurai8
Jun 3 '16 at 19:32
1
1
If I had to guess it is based on which snake moves first. Which snake moves first? Well... maybe it is the one that was created first. Or they get a random id, and they are enumerated by id. I am mostly just guessing here.
– Sumurai8
Jun 3 '16 at 19:32
If I had to guess it is based on which snake moves first. Which snake moves first? Well... maybe it is the one that was created first. Or they get a random id, and they are enumerated by id. I am mostly just guessing here.
– Sumurai8
Jun 3 '16 at 19:32
add a comment |
3 Answers
3
active
oldest
votes
up vote
2
down vote
For the most part, head on collisions seem to be random. For many occurrences, the boosting snake seems to have the advantage. The mechanics of deciding who wins in a head on collision have not been fully figured out yet, but the mass definitely had nothing to do with it.
Here's a great debate about some people who did tests on Reddit.
Addition:
When you are boosting the game predicts where you will be next, so you could be going a different way but you still die when they did not run in front of you. This is one of the flaws of the game, so if you are boosting the game will assume when your in contact, you've already past them, so they will be killed. If you are both boosting, it would end out the same as if neither of you are boosting, resulting it as random.
edited Jun 3 '16 at 22:27
Riker
1,232729
answered Jun 3 '16 at 19:31
ethanflips
412216
To clarify, the cases I'm referring to are when both snakes are boosting. I clarified my question.
– Robert Cartaino♦
Jun 3 '16 at 19:39
@RobertCartaino With boosting there is a glitch... Let me clarify my answer...
– ethanflips
Jun 3 '16 at 19:42
@RobertCartaino there, I hope that helps
– ethanflips
Jun 3 '16 at 19:50
add a comment |
up vote
0
down vote
I think that it actually works like this as the example below.
Snake A's mass is 3k, while Snake B's mass is 5k. They both have a head-on collision, and Snake B survived because his mass is bigger.
answered Sep 17 at 6:51
oliverthegreat
279
add a comment |
up vote
0
down vote
Simply, the larger snake (more mass) wins in a head-on collision.
answered 11 mins ago
Michael
1
New contributor
Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
For the most part, head on collisions seem to be random. For many occurrences, the boosting snake seems to have the advantage. The mechanics of deciding who wins in a head on collision have not been fully figured out yet, but the mass definitely had nothing to do with it.
Here's a great debate about some people who did tests on Reddit.
Addition:
When you are boosting the game predicts where you will be next, so you could be going a different way but you still die when they did not run in front of you. This is one of the flaws of the game, so if you are boosting the game will assume when your in contact, you've already past them, so they will be killed. If you are both boosting, it would end out the same as if neither of you are boosting, resulting it as random.
edited Jun 3 '16 at 22:27
Riker
1,232729
answered Jun 3 '16 at 19:31
ethanflips
412216
To clarify, the cases I'm referring to are when both snakes are boosting. I clarified my question.
– Robert Cartaino♦
Jun 3 '16 at 19:39
@RobertCartaino With boosting there is a glitch... Let me clarify my answer...
– ethanflips
Jun 3 '16 at 19:42
@RobertCartaino there, I hope that helps
– ethanflips
Jun 3 '16 at 19:50
add a comment |
up vote
2
down vote
For the most part, head on collisions seem to be random. For many occurrences, the boosting snake seems to have the advantage. The mechanics of deciding who wins in a head on collision have not been fully figured out yet, but the mass definitely had nothing to do with it.
Here's a great debate about some people who did tests on Reddit.
Addition:
When you are boosting the game predicts where you will be next, so you could be going a different way but you still die when they did not run in front of you. This is one of the flaws of the game, so if you are boosting the game will assume when your in contact, you've already past them, so they will be killed. If you are both boosting, it would end out the same as if neither of you are boosting, resulting it as random.
edited Jun 3 '16 at 22:27
Riker
1,232729
answered Jun 3 '16 at 19:31
ethanflips
412216
To clarify, the cases I'm referring to are when both snakes are boosting. I clarified my question.
– Robert Cartaino♦
Jun 3 '16 at 19:39
@RobertCartaino With boosting there is a glitch... Let me clarify my answer...
– ethanflips
Jun 3 '16 at 19:42
@RobertCartaino there, I hope that helps
– ethanflips
Jun 3 '16 at 19:50
add a comment |
up vote
2
down vote
up vote
2
down vote
For the most part, head on collisions seem to be random. For many occurrences, the boosting snake seems to have the advantage. The mechanics of deciding who wins in a head on collision have not been fully figured out yet, but the mass definitely had nothing to do with it.
Here's a great debate about some people who did tests on Reddit.
Addition:
When you are boosting the game predicts where you will be next, so you could be going a different way but you still die when they did not run in front of you. This is one of the flaws of the game, so if you are boosting the game will assume when your in contact, you've already past them, so they will be killed. If you are both boosting, it would end out the same as if neither of you are boosting, resulting it as random.
edited Jun 3 '16 at 22:27
Riker
1,232729
answered Jun 3 '16 at 19:31
ethanflips
412216
For the most part, head on collisions seem to be random. For many occurrences, the boosting snake seems to have the advantage. The mechanics of deciding who wins in a head on collision have not been fully figured out yet, but the mass definitely had nothing to do with it.
Here's a great debate about some people who did tests on Reddit.
Addition:
When you are boosting the game predicts where you will be next, so you could be going a different way but you still die when they did not run in front of you. This is one of the flaws of the game, so if you are boosting the game will assume when your in contact, you've already past them, so they will be killed. If you are both boosting, it would end out the same as if neither of you are boosting, resulting it as random.
edited Jun 3 '16 at 22:27
Riker
1,232729
answered Jun 3 '16 at 19:31
ethanflips
412216
edited Jun 3 '16 at 22:27
Riker
1,232729
edited Jun 3 '16 at 22:27
Riker
1,232729
edited Jun 3 '16 at 22:27
Riker
1,232729
1,232729
answered Jun 3 '16 at 19:31
ethanflips
412216
answered Jun 3 '16 at 19:31
ethanflips
412216
answered Jun 3 '16 at 19:31
ethanflips
412216
412216
To clarify, the cases I'm referring to are when both snakes are boosting. I clarified my question.
– Robert Cartaino♦
Jun 3 '16 at 19:39
@RobertCartaino With boosting there is a glitch... Let me clarify my answer...
– ethanflips
Jun 3 '16 at 19:42
@RobertCartaino there, I hope that helps
– ethanflips
Jun 3 '16 at 19:50
add a comment |
To clarify, the cases I'm referring to are when both snakes are boosting. I clarified my question.
– Robert Cartaino♦
Jun 3 '16 at 19:39
@RobertCartaino With boosting there is a glitch... Let me clarify my answer...
– ethanflips
Jun 3 '16 at 19:42
@RobertCartaino there, I hope that helps
– ethanflips
Jun 3 '16 at 19:50
To clarify, the cases I'm referring to are when both snakes are boosting. I clarified my question.
– Robert Cartaino♦
Jun 3 '16 at 19:39
To clarify, the cases I'm referring to are when both snakes are boosting. I clarified my question.
– Robert Cartaino♦
Jun 3 '16 at 19:39
@RobertCartaino With boosting there is a glitch... Let me clarify my answer...
– ethanflips
Jun 3 '16 at 19:42
@RobertCartaino With boosting there is a glitch... Let me clarify my answer...
– ethanflips
Jun 3 '16 at 19:42
@RobertCartaino there, I hope that helps
– ethanflips
Jun 3 '16 at 19:50
@RobertCartaino there, I hope that helps
– ethanflips
Jun 3 '16 at 19:50
add a comment |
up vote
0
down vote
I think that it actually works like this as the example below.
Snake A's mass is 3k, while Snake B's mass is 5k. They both have a head-on collision, and Snake B survived because his mass is bigger.
answered Sep 17 at 6:51
oliverthegreat
279
add a comment |
up vote
0
down vote
I think that it actually works like this as the example below.
Snake A's mass is 3k, while Snake B's mass is 5k. They both have a head-on collision, and Snake B survived because his mass is bigger.
answered Sep 17 at 6:51
oliverthegreat
279
add a comment |
up vote
0
down vote
up vote
0
down vote
I think that it actually works like this as the example below.
Snake A's mass is 3k, while Snake B's mass is 5k. They both have a head-on collision, and Snake B survived because his mass is bigger.
answered Sep 17 at 6:51
oliverthegreat
279
I think that it actually works like this as the example below.
Snake A's mass is 3k, while Snake B's mass is 5k. They both have a head-on collision, and Snake B survived because his mass is bigger.
answered Sep 17 at 6:51
oliverthegreat
279
answered Sep 17 at 6:51
oliverthegreat
279
answered Sep 17 at 6:51
oliverthegreat
279
answered Sep 17 at 6:51
oliverthegreat
279
279
add a comment |
add a comment |
up vote
0
down vote
Simply, the larger snake (more mass) wins in a head-on collision.
answered 11 mins ago
Michael
1
New contributor
Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
0
down vote
Simply, the larger snake (more mass) wins in a head-on collision.
answered 11 mins ago
Michael
1
New contributor
Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
0
down vote
up vote
0
down vote
Simply, the larger snake (more mass) wins in a head-on collision.
answered 11 mins ago
Michael
1
New contributor
Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Simply, the larger snake (more mass) wins in a head-on collision.
answered 11 mins ago
Michael
1
New contributor
Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 11 mins ago
Michael
1
New contributor
Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 11 mins ago
Michael
1
answered 11 mins ago
Michael
1
1
New contributor
Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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1
If I had to guess it is based on which snake moves first. Which snake moves first? Well... maybe it is the one that was created first. Or they get a random id, and they are enumerated by id. I am mostly just guessing here.
– Sumurai8
Jun 3 '16 at 19:32